8c^2+42c+27=0

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Solution for 8c^2+42c+27=0 equation: 



8c^2+42c+27=0

a = 8; b = 42; c = +27;
Δ = b2-4ac
Δ = 422-4·8·27
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$


$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-30}{2*8}=\frac{-72}{16}
=-4+1/2
$


$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+30}{2*8}=\frac{-12}{16}
=-3/4
$

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